In Fig. 6.13, ∠BAC = 90°, AD ⟂ BC and ∠BAD = 50°, then ∠ACD is
(a) 50°
(b) 40°
(c) 70°
(d) 60°
∠BAD = 50°. ∠BAC = 90°. So ∠DAC = 40°. Right triangle splits. ∠ACD = 50°.