In ΔABC, ∠A = 100°, AD bisects ∠A and AD ⟂ BC. Then, ∠B is equal to
(a) 80°
(b) 20°
(c) 40°
(d) 30°
AD bisects ∠A = 100°, so each part = 50°. AD ⟂ BC gives right triangle. Hence ∠B = 40°.