In ΔPQR, if 3∠P = 4∠Q = 6∠R, calculate the angles of the triangle.
∠P = 80°, ∠Q = 60°, ∠R = 40°
Let ∠P = 2k, ∠Q = 3k, ∠R = 1.5k. Sum = 6.5k = 180 ⇒ k = 20 ⇒ P = 80°, Q = 60°, R = 40°.