NCERT Solutions
Class 10 - Mathematics - Chapter 4: QUADRATIC EQUATIONS
Exercise 4.2

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Question. 1

Find the roots of the following quadratic equations by factorisation:

(i) \(x^2 - 3x - 10 = 0\)

(ii) \(2x^2 + x - 6 = 0\)

(iii) \(\sqrt{2}x^2 + 7x + 5\sqrt{2} = 0\)

(iv) \(2x^2 - x + \frac{1}{8} = 0\)

(v) \(100x^2 - 20x + 1 = 0\)

Answer:

(i) \(-2, 5\)

(ii) \(-2, \frac{3}{2}\)

(iii) \(-\frac{5}{\sqrt{2}}, -\sqrt{2}\)

(iv) \(\frac{1}{4}, \frac{1}{4}\)

(v) \(\frac{1}{10}, \frac{1}{10}\)

Question. 2

Solve the problems given in Example 1.

Answer:

(i) \(9, 36\)

(ii) \(25, 30\)

Question. 3

Find two numbers whose sum is 27 and product is 182.

Answer:

Numbers are 13 and 14.

Question. 4

Find two consecutive positive integers, the sum of whose squares is 365.

Answer:

Positive integers are 13 and 14.

Question. 5

The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.

Answer:

5 cm and 12 cm

Question. 6

A cottage industry produces a certain number of pottery articles in a day. The cost of production of each article is 3 rupees more than twice the number of articles produced that day. If the total cost of production is ₹90, find the number of articles produced and the cost of each article.

Answer:

Number of articles = 6, Cost of each article = ₹15

Disclaimer:The solutions provided here are prepared independently for educational purposes only. This material is not an official NCERT publication.
NCERT Solutions Class 10 – Mathematics – Chapter 4: QUADRATIC EQUATIONS – Exercise 4.2 | Detailed Answers