NCERT Solutions
Class 10 - Mathematics - Chapter 5: ARITHMETIC PROGRESSIONS - Exercise 5.2
Question 10

Question. 10

The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Answer:

1

Detailed Answer with Explanation:

Step 1: Recall the nth term formula of an AP.

For an arithmetic progression (AP), the nth term is given by:

\[a_n = a + (n - 1)d\]

where \(a\) is the first term and \(d\) is the common difference.

Step 2: Write expressions for the 10th and 17th terms.

10th term:

\[a_{10} = a + 9d\]

17th term:

\[a_{17} = a + 16d\]

Step 3: Use the given condition.

The 17th term exceeds the 10th term by 7. So:

\[a_{17} - a_{10} = 7\]

Substitute the expressions:

\[(a + 16d) - (a + 9d) = 7\]

Step 4: Simplify the equation.

\[a + 16d - a - 9d = 7\]

\[7d = 7\]

Step 5: Solve for \(d\).

\[d = \dfrac{7}{7} = 1\]

Conclusion: The common difference of the AP is 1.

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