NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 8: Ratio & Proportion
Fill in the Blanks

In questions 35 to 46, fill in the blanks to make the statements true.

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Question. 35

A ratio is a form of comparison by _____.

Answer:

A ratio is a form of comparison by division.

Question. 36

20 m : 70 m = Rs 8 : Rs ____.

Answer:

20 m : 70 m = Rs 8 : Rs 28.

Question. 37

There is a number in the box \(\square\) such that \(\square,\;24,\;9,\;12\) are in proportion. The number in the box is ____.

Answer:

There is a number in the box such that 18, 24, 9, 12 are in proportion. The number in the box is 18.

Question. 38

If two ratios are equal, then they are in ____.

Answer:

If two ratios are equal, then they are in proportion.

Question. 39

The ratio of the perimeter of the boundary of the shaded portion to the perimeter of the whole figure is ____.

Fig 8.2

Answer:

The ratio is 3 : 7.

Question. 40

The ratio of the area of the shaded portion to that of the whole figure is ____.

Fig 8.2

Answer:

The ratio is 1 : 6.

Question. 41

Sleeping time of a python in a 24 hour clock is represented by the shaded portion in Fig. 8.3. The ratio of sleeping time to awaking time is ____.

Fig 8.3

Answer:

The ratio is 3 : 1.

Question. 42

A ratio expressed in lowest form has no common factor other than _____ in its terms.

Answer:

A ratio expressed in lowest form has no common factor other than one in its terms.

Question. 43

To find the ratio of two quantities, they must be expressed in ____ units.

Answer:

To find the ratio of two quantities, they must be expressed in same units.

Question. 44

Ratio of 5 paise to 25 paise is the same as the ratio of 20 paise to ____.

Answer:

Ratio of 5 paise to 25 paise is the same as the ratio of 20 paise to 100 paise (i.e., 1 Rupee).

Question. 45

Saturn and Jupiter take 9 hours 56 minutes and 10 hours 40 minutes, respectively for one spin on their axes. The ratio of the time taken by Saturn and Jupiter in lowest form is ____.

Answer:

The ratio is 149 : 160.

Question. 46

10 g of caustic soda dissolved in 100 mL of water makes a solution of caustic soda. Amount of caustic soda needed for 1 litre of water to make the same type of solution is ____.

Answer:

100 g.

NCERT Exemplar Solutions Class 6 – Mathematics – Unit 8: Ratio & Proportion – Fill in the Blanks | Detailed Answers