NCERT Exemplar Solutions
Class 6 - Mathematics - Unit 8: Ratio & Proportion
Fill in the Blanks

In questions 35 to 46, fill in the blanks to make the statements true.

Question. 35

A ratio is a form of comparison by _____.

Answer:

A ratio is a form of comparison by division.

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Question. 36

20 m : 70 m = Rs 8 : Rs ____.

Answer:

20 m : 70 m = Rs 8 : Rs 28.

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Question. 37

There is a number in the box \(\square\) such that \(\square,\;24,\;9,\;12\) are in proportion. The number in the box is ____.

Answer:

There is a number in the box such that 18, 24, 9, 12 are in proportion. The number in the box is 18.

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Question. 38

If two ratios are equal, then they are in ____.

Answer:

If two ratios are equal, then they are in proportion.

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Question. 39

The ratio of the perimeter of the boundary of the shaded portion to the perimeter of the whole figure is ____.

Fig 8.2

Answer:

The ratio is 3 : 7.

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Question. 40

The ratio of the area of the shaded portion to that of the whole figure is ____.

Fig 8.2

Answer:

The ratio is 1 : 6.

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Question. 41

Sleeping time of a python in a 24 hour clock is represented by the shaded portion in Fig. 8.3. The ratio of sleeping time to awaking time is ____.

Fig 8.3

Answer:

The ratio is 3 : 1.

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Question. 42

A ratio expressed in lowest form has no common factor other than _____ in its terms.

Answer:

A ratio expressed in lowest form has no common factor other than one in its terms.

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Question. 43

To find the ratio of two quantities, they must be expressed in ____ units.

Answer:

To find the ratio of two quantities, they must be expressed in same units.

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Question. 44

Ratio of 5 paise to 25 paise is the same as the ratio of 20 paise to ____.

Answer:

Ratio of 5 paise to 25 paise is the same as the ratio of 20 paise to 100 paise (i.e., 1 Rupee).

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Question. 45

Saturn and Jupiter take 9 hours 56 minutes and 10 hours 40 minutes, respectively for one spin on their axes. The ratio of the time taken by Saturn and Jupiter in lowest form is ____.

Answer:

The ratio is 149 : 160.

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Question. 46

10 g of caustic soda dissolved in 100 mL of water makes a solution of caustic soda. Amount of caustic soda needed for 1 litre of water to make the same type of solution is ____.

Answer:

100 g.

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NCERT Exemplar Solutions Class 6 – Mathematics – Unit 8: Ratio & Proportion – Fill in the Blanks | Detailed Answers