NCERT Exemplar Solutions - Class 6 - Mathematics - Unit 8: Ratio & Proportion
Missing Numbers in the Box

In questions 11 to 15, find the missing number in the box in each of the proportions:

Quick Links to Questions

Q. 11
Q. 12
Q. 13
Q. 14
Q. 15

Question. 11

11. \( \dfrac{3}{5} = \dfrac{\square}{20} \)

Answer

\( \dfrac{3}{5} = \dfrac{12}{20} \)

Step by Step Solution

\(\dfrac{3}{5} = \dfrac{x}{20} \Rightarrow x = \dfrac{3 \times 20}{5} = 12\).

Question. 12

12. \( \dfrac{\square}{18} = \dfrac{2}{9} \)

Answer

\( \dfrac{4}{18} = \dfrac{2}{9} \)

Step by Step Solution

\(\dfrac{x}{18} = \dfrac{2}{9} \Rightarrow x = \dfrac{18 \times 2}{9} = 4\).

Question. 13

13. \( \dfrac{8}{\square} = \dfrac{3.2}{4} \)

Answer

\( \dfrac{8}{10} = \dfrac{3.2}{4} \)

Step by Step Solution

\(\dfrac{8}{x} = \dfrac{3.2}{4} \Rightarrow 8 \times 4 = 3.2 \times x \Rightarrow x = 10\).

Question. 14

14. \( \dfrac{\square}{45} = \dfrac{16}{40} = \dfrac{24}{\square} \)

Answer

\( \dfrac{18}{45} = \dfrac{16}{40} = \dfrac{24}{60} \)

Step by Step Solution

\(\dfrac{16}{40} = \dfrac{2}{5}\). For \(x/45 = 2/5\), \(x=18\). For \(24/y = 2/5\), \(y=60\).

Question. 15

15. \( \dfrac{16}{36} = \dfrac{\square}{63} = \dfrac{36}{\square} = \dfrac{\square}{117} \)

Answer

\( \dfrac{16}{36} = \dfrac{28}{63} = \dfrac{36}{81} = \dfrac{52}{117} \)

Step by Step Solution

Simplify first ratio: \(16/36 = 4/9\). For numerator with 63: \(x/63=4/9 \Rightarrow x=28\). For denominator with 36: \(36/y=4/9 \Rightarrow y=81\). For numerator with 117: \(z/117=4/9 \Rightarrow z=52\).

Disclaimer:The questions are taken from NCERT Exemplar, which is the copyright of NCERT. The solutions provided here are prepared independently for educational purposes only. This material is not an official NCERT publication.