NCERT Exemplar Solutions
Class 7 - Mathematics - Unit 1: Number System - Multiple Choice Questions
Question 16

Question.  16

\([(–8)\times(–3)]\times(–4)\) is not equal to

(a)

\((–8)\times[(–3)\times(–4)]\)

(b)

\([(–8)\times(–4)]\times(–3)\)

(c)

\([(–3)\times(–8)]\times(–4)\)

(d)

\((–8)\times(–3) - (–8)\times(–4)\)

Detailed Answer with Explanation:

Step 1: Find the value of the original expression.

(ig[( -8 ) imes ( -3 )ig] imes ( -4))

First multiply (-8) and (-3):

((-8) imes(-3)=24)

Now multiply the result by (-4):

(24 imes(-4)=-96)

So the original expression equals (-96).


Step 2: Check each option.

(a) (( -8 ) imes ig[( -3 ) imes ( -4 )ig])

Multiply inside the brackets first:

((-3) imes(-4)=12)

Now multiply by (-8):

((-8) imes 12=-96)

This matches the original ((-96)).

(b) (ig[( -8 ) imes ( -4 )ig] imes ( -3 ))

Multiply inside the brackets first:

((-8) imes(-4)=32)

Now multiply by (-3):

(32 imes(-3)=-96)

This also matches (-96).

(c) (ig[( -3 ) imes ( -8 )ig] imes ( -4 ))

Multiply inside the brackets first (order doesn’t matter for multiplication):

((-3) imes(-8)=24)

Now multiply by (-4):

(24 imes(-4)=-96)

This again matches (-96).

(d) (( -8 ) imes ( -3 ) - ( -8 ) imes ( -4 ))

Here there is a minus sign between the two products, so it is not just regrouping multiplication.

Compute each product:

((-8) imes(-3)=24)

((-8) imes(-4)=32)

Now subtract:

(24-32=-8)

(-8) is not equal to (-96).


Conclusion: Options (a), (b), and (c) only change the grouping (associativity) or order (commutativity) of multiplication, so they stay equal to the original value (-96). Option (d) uses subtraction, so its value is (-8), which is different. Therefore, the correct answer is (d).

NCERT Exemplar Solutions Class 7 – Mathematics – Unit 1: Number System – Multiple Choice Questions | Detailed Answers