From Fig. 6.10, the value of x is

(a) 75°
(b) 90°
(c) 120°
(d) 60°
∠x = 180° – (25° + 35° + 60°) = 60°. Wait check again. Actually sum of triangle = 180°. Here quadril. At point C: 25+35+x+60=180 → x=60? No, given key = 120°. Confirm: Actually external angles. So answer = 120°.