NCERT Exemplar Solutions
Class 7 - Mathematics - Unit 8: Rational Numbers

Fill in the Blanks

\(-\dfrac{3}{8}\) is a _____ rational number.

1 is a _____ rational number.

The standard form of \(-\dfrac{8}{-36}\) is _____.

The standard form of \(\dfrac{18}{-24}\) is _____.

On a number line, \(-\dfrac{1}{2}\) is to the _____ of zero (0).

On a number line, \(\dfrac{4}{3}\) is to the _____ of zero (0).

\(-\dfrac{1}{2}\) is _____ than \(\dfrac{1}{5}\).

\(-\dfrac{3}{5}\) is _____ than 0.

\(-\dfrac{16}{24}\) and \(\dfrac{20}{-16}\) represent _____ rational numbers.

\(-\dfrac{27}{45}\) and \(-\dfrac{3}{5}\) represent _____ rational numbers.

Additive inverse of \(\dfrac{2}{3}\) is _____.

\(-\dfrac{3}{5} + \dfrac{2}{5} = \) _____.

\(-\dfrac{5}{6} + -\dfrac{1}{6} = \) _____.

\(\dfrac{3}{4} \times ( -\dfrac{2}{3} ) = \) _____.

\(-\dfrac{5}{3} \times ( -\dfrac{3}{5} ) = \) _____.

\(-\dfrac{6}{7} = \dfrac{__}{42}\)

\(\dfrac{1}{2} = \dfrac{6}{__}\)

\(-\dfrac{2}{9} - \dfrac{7}{9} = \) _____.

\(-\dfrac{7}{8} \; \Box \; \dfrac{8}{9}\)

\(\dfrac{3}{7} \; \Box \; \dfrac{-5}{6}\)

\(\dfrac{5}{6} \; \Box \; \dfrac{8}{4}\)

\(-\dfrac{9}{7} \; \Box \; \dfrac{4}{-7}\)

\(\dfrac{8}{8} \; \Box \; \dfrac{2}{2}\)

The reciprocal of _____ does not exist.

The reciprocal of 1 is _____.

\(-\dfrac{3}{7} \div ( -\dfrac{7}{3} ) = \) _____

\(0 \div ( -\dfrac{5}{6} ) = \) _____

\(0 \times ( -\dfrac{5}{6} ) = \) _____

_____ \(\times ( -\dfrac{2}{5} ) = 1\)

The standard form of rational number -1 is _____.

If m is a common divisor of a and b, then \(\dfrac{a}{b} = \dfrac{a \div m}{\_\_\_}\)

If p and q are positive integers, then \(\dfrac{p}{q}\) is a _____ rational number and \(\dfrac{p}{-q}\) is a _____ rational number.

Two rational numbers are said to be equivalent or equal, if they have the same _____ form.

If \(\dfrac{p}{q}\) is a rational number, then q cannot be _____.