If \(x=\dfrac{1}{10}\) and \(y=\dfrac{-3}{8}\), then evaluate \(x+y, x-y, x×y, x÷y\).
(i) \(x+y = -\dfrac{11}{40}\)
(ii) \(x-y = \dfrac{19}{40}\)
(iii) \(x×y = -\dfrac{3}{80}\)
(iv) \(x÷y = -\dfrac{4}{15}\)
(i) \(\dfrac{1}{10} + \dfrac{-3}{8} = \dfrac{4-15}{40} = -\dfrac{11}{40}\).
(ii) \(\dfrac{1}{10} - \dfrac{-3}{8} = \dfrac{4+15}{40} = \dfrac{19}{40}\).
(iii) \(\dfrac{1}{10} × \dfrac{-3}{8} = -\dfrac{3}{80}\).
(iv) \(\dfrac{1}{10} ÷ \dfrac{-3}{8} = \dfrac{1}{10} × \dfrac{-8}{3} = -\dfrac{8}{30} = -\dfrac{4}{15}\).