NCERT Solutions
Class 10 - Mathematics - Chapter 5: ARITHMETIC PROGRESSIONS - Exercise 5.3
Question 14

Question. 14

Find the sum of the odd numbers between 0 and 50.

Answer:

\(625\)

Detailed Answer with Explanation:

Step 1: Identify the sequence of odd numbers.

The odd numbers between 0 and 50 are:

\[1, 3, 5, 7, \ldots, 49\]

This is an arithmetic progression (AP) with:

First term \(a = 1\), common difference \(d = 2\), last term \(l = 49\).

Step 2: Find the number of terms.

Use the nth-term formula:

\[a_n = a + (n - 1)d\]

Put \(a_n = 49\):

\[49 = 1 + (n - 1)2\]

\[49 - 1 = 2(n - 1)\]

\[48 = 2(n - 1)\]

\[n - 1 = 24 \Rightarrow n = 25\]

So, there are 25 odd numbers.

Step 3: Use the sum formula for an AP.

\[S_n = \dfrac{n}{2}(a + l)\]

Substitute \(n = 25\), \(a = 1\), \(l = 49\):

\[S_{25} = \dfrac{25}{2}(1 + 49) = \dfrac{25}{2} \cdot 50 = 25 \cdot 25 = 625\]

Conclusion: The sum of all odd numbers between 0 and 50 is 625.

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