For some integer \(q\), every odd integer is of the form
\(q\)
\(q + 1\)
\(2q\)
\(2q + 1\)



Step 1: Recall that even integers are always multiples of 2.
So we can write any even integer as:
\(2q\), where \(q\) is some integer.
Step 2: Odd integers are always one more than an even integer.
Therefore, if an even number is \(2q\), then the next odd number is:
\(2q + 1\).
Step 3: This shows that every odd integer can be expressed in the form:
\(2q + 1\).
Answer: Option D (\(2q + 1\))