NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 1: Real Numbers - Exercise 1.3 - Short Answer Questions
Question 13

Question. 13

Write the denominator of the rational number \(\dfrac{257}{5000}\) in the form 2m × 5n, where m, n are non-negative integers. Hence, write its decimal expansion, without actual division.

Answer:

Denominator: \(2^3 \cdot 5^4\). Decimal: 0.0514

Detailed Answer with Explanation:

Step 1: Prime factorisation of the denominator.

We start with the denominator \(5000\).

Break it down: \(5000 = 5 \times 1000\).

Now, \(1000 = 10^3 = (2 \cdot 5)^3 = 2^3 \cdot 5^3\).

So, \(5000 = 5 \times (2^3 \cdot 5^3) = 2^3 \cdot 5^4\).

Thus, in the required form, the denominator is \(2^3 \cdot 5^4\).

Step 2: Find the number of decimal places.

The highest power among \(2^3\) and \(5^4\) is \(5^4\).

This means the decimal expansion will terminate after 4 places.

Step 3: Write the decimal without division.

The fraction is \(\dfrac{257}{5000}\).

We can think of this as dividing numerator and denominator in steps.

First, divide \(257\) by \(5\):

\(\dfrac{257}{5} = 51.4\).

Now we still need to divide by \(1000\) (since \(5000 = 5 \times 1000\)).

So, \(\dfrac{257}{5000} = \dfrac{51.4}{1000} = 0.0514\).

Final Answer:

The denominator in prime form is \(2^3 \cdot 5^4\). The decimal expansion is \(0.0514\).

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 1: Real Numbers – Exercise 1.3 - Short Answer Questions | Detailed Answers