NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 4: Quadatric Equation
Exercise 4.3

Finding roots by the quadratic formula and by factorisation (with clear beginner steps).

Question. 1

Find the roots of the quadratic equations by using the quadratic formula in each of the following:

(i) \(2x^2 - 3x - 5 = 0\)

(ii) \(5x^2 + 13x + 8 = 0\)

(iii) \(-3x^2 + 5x + 12 = 0\)

(iv) \(-x^2 + 7x - 10 = 0\)

(v) \(x^2 + 2\sqrt{2}\,x - 6 = 0\)

(vi) \(x^2 - 3\sqrt{5}\,x + 10 = 0\)

(vii) \(\dfrac{1}{2}x^2 - \sqrt{11}\,x + 1 = 0\)

Answer:

(i) \(x=\dfrac{5}{2}\), \(x=-1\)

(ii) \(x=-1\), \(x=-\dfrac{8}{5}\)

(iii) \(x=3\), \(x=-\dfrac{4}{3}\)

(iv) \(x=5\), \(x=2\)

(v) \(x=\sqrt{2}\), \(x=-3\sqrt{2}\)

(vi) \(x=2\sqrt{5}\), \(x=\sqrt{5}\)

(vii) \(x=\sqrt{11}+3\), \(x=\sqrt{11}-3\)

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Question. 2

Find the roots of the following quadratic equations by the factorisation method:

(i) \(2x^2 + \dfrac{5}{3}x - 2 = 0\)

(ii) \(\dfrac{2}{5}x^2 - x - \dfrac{3}{5} = 0\)

(iii) \(3\sqrt{2}\,x^2 - 5x - \sqrt{2} = 0\)

(iv) \(3x^2 + 5\sqrt{5}\,x - 10 = 0\)

(v) \(21x^2 - 2x + \dfrac{1}{21} = 0\)

Answer:

(i) \(x=-\dfrac{3}{2}\), \(x=\dfrac{2}{3}\)

(ii) \(x=-\dfrac{1}{2}\), \(x=3\)

(iii) \(x=\sqrt{2}\), \(x=-\dfrac{\sqrt{2}}{6}\)

(iv) \(x=\dfrac{\sqrt{5}}{3}\), \(x=-2\sqrt{5}\)

(v) double root \(x=\dfrac{1}{21}\)

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NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 4: Quadatric Equation – Exercise 4.3 | Detailed Answers