NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 1: Real Numbers - Exercise 1.1 - Multiple Choice Questions

Question 9

The required number is the least common multiple (LCM) of 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.

The highest powers of primes within this range are: \(2^3, 3^2, 5, 7\).

So, \(\text{LCM} = 2^3 \times 3^2 \times 5 \times 7 = 2520\).

Therefore, the least number divisible by all the numbers from 1 to 10 is 2520.