The product of a non-zero rational and an irrational number is
always irrational
always rational
rational or irrational
one




Let \(r \neq 0\) be a rational number and \(\alpha\) an irrational number.
If their product \(r\alpha\) were rational, then dividing it by the non-zero rational \(r\) would give \(\alpha = \dfrac{r\alpha}{r}\), which would make \(\alpha\) rational. This is a contradiction.
Hence, the product is always irrational.