NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 10: Construction - Exercise 10.1
Question 2

Question.  2

To divide a line segment AB in the ratio 4:7, a ray AX is drawn first such that ∠BAX is an acute angle and then points A₁, A₂, A₃, ... are located at equal distances on the ray AX and the point B is joined to

(A)

A12

(B)

A11

(C)

A10

(D)

A9

Detailed Answer with Explanation:

Step 1: The ratio given is \(4:7\).

Step 2: Add the numbers of the ratio: \(4 + 7 = 11\). This means we must divide AB into 11 equal parts.

Step 3: On ray AX, we mark 11 points at equal distances: A₁, A₂, A₃ … A₁₁.

Step 4: To divide AB, we always join the last point (A₁₁) to B.

Step 5: Then we draw a line parallel to A₁₁B from A₄ (because we want the first part of ratio = 4). This parallel line will cut AB at the required division point.

Final Answer: The point joined to B is A₁₁. So the correct option is A12.

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 10: Construction – Exercise 10.1 | Detailed Answers