NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 10: Construction - Exercise 10.1
Question 1

Question.  1

To divide a line segment AB in the ratio 5:7, first a ray AX is drawn so that ∠BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is

(A)

8

(B)

10

(C)

11

(D)

12

Detailed Answer with Explanation:

Step 1: The question asks us to divide a line segment AB in the ratio 5:7.

Step 2: The ratio 5:7 means AB is divided into two parts. One part is 5 units long and the other part is 7 units long.

Step 3: To do this by construction, we first draw a ray AX making an acute angle with AB.

Step 4: On this ray AX, we mark equal distances (like equal steps).

Step 5: The number of equal steps (points) must be equal to the total parts in the ratio.

Step 6: Add the numbers in the ratio: 5 + 7 = 12.

Step 7: So, we must mark 12 equal points on AX.

Final Answer: 12

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 10: Construction – Exercise 10.1 | Detailed Answers