NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 10: Construction - Exercise 10.1
Question 5

Question.  5

To construct a triangle similar to a given ΔABC with its sides 85 of the corresponding sides of ΔABC, draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is

(A)

5

(B)

8

(C)

13

(D)

3

Detailed Answer with Explanation:

Step 1: The scale factor of the required triangle is \(\dfrac{8}{5}\). This means each side of the new triangle will be 8 parts for every 5 parts of the original triangle.

Step 2: When constructing similar triangles using the method of division on a ray (ray BX here), we divide the ray into a number of equal parts equal to the denominator and numerator added together.

Step 3: Why do we add? - The denominator (5) shows the parts that represent the original triangle. - The numerator (8) shows the parts that represent the scaled triangle. - To correctly map one triangle onto the other, we need both sets of points, so we take total = 5 + 8.

Step 4: So, we need to mark 13 equal divisions (points) on ray BX.

Final Answer: 13

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 10: Construction – Exercise 10.1 | Detailed Answers