NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 3: Pair of Linear Equations in Two Variables - Exercise 3.3
Question 7

Question. 7

If \(2x + y = 23\) and \(4x - y = 19\), find the values of \(5y - 2x\) and \(\dfrac{y}{x} - 2\).

Answer:

\(5y - 2x = 31\) and \(\dfrac{y}{x} - 2 = -\dfrac{5}{7}\).

Detailed Answer with Explanation:

Step 1: Write the two equations clearly.

Equation (1): \(2x + y = 23\)

Equation (2): \(4x - y = 19\)

Step 2: Add the two equations to remove \(y\).

\((2x + y) + (4x - y) = 23 + 19\)

\(2x + 4x + y - y = 42\)

\(6x = 42\)

So, \(x = 7\).

Step 3: Put the value of \(x\) into Equation (1).

Equation (1): \(2x + y = 23\)

\(2(7) + y = 23\)

\(14 + y = 23\)

So, \(y = 23 - 14 = 9\).

Step 4: Now calculate \(5y - 2x\).

\(5y - 2x = 5(9) - 2(7)\)

\(= 45 - 14\)

\(= 31\)

Step 5: Calculate \(\dfrac{y}{x} - 2\).

\(\dfrac{y}{x} - 2 = \dfrac{9}{7} - 2\)

Write 2 as \(\dfrac{14}{7}\).

So, \(\dfrac{9}{7} - \dfrac{14}{7} = \dfrac{-5}{7}\).

Final Answer:

\(5y - 2x = 31\)

\(\dfrac{y}{x} - 2 = -\dfrac{5}{7}\)

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 3: Pair of Linear Equations in Two Variables – Exercise 3.3 | Detailed Answers