NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 5: Arithematic Progressions - Exercise 5.1
Question 5

Question.  5

The first four terms of an AP with \(a=-2\) and \(d=-2\) are

(A)

−2, 0, 2, 4

(B)

−2, 4, −8, 16

(C)

−2, −4, −6, −8

(D)

−2, −4, −8, −16

Detailed Answer with Explanation:

We are given:

  • First term (\(a\)) = −2
  • Common difference (\(d\)) = −2

An Arithmetic Progression (AP) means we get the next term by adding the common difference (\(d\)) to the previous term.

Step 1: First term = −2

Step 2: To find the second term, add \(d\) to the first term:
\(-2 + (-2) = -4\)

Step 3: To find the third term, add \(d\) to the second term:
\(-4 + (-2) = -6\)

Step 4: To find the fourth term, add \(d\) to the third term:
\(-6 + (-2) = -8\)

So, the first four terms are: −2, −4, −6, −8.

Correct option: C

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 5: Arithematic Progressions – Exercise 5.1 | Detailed Answers