NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 5: Arithematic Progressions - Exercise 5.1
Question 8

Question.  8

Which term of the AP \(21,42,63,84,\ldots\) is \(210\)?

(A)

9th

(B)

10th

(C)

11th

(D)

12th

Detailed Answer with Explanation:

Step 1: In an Arithmetic Progression (AP), the first term is called a and the common difference is called d.

Here, the AP is \(21, 42, 63, 84, \ldots\).

So, \(a = 21\) and \(d = 42 - 21 = 21\).

Step 2: The formula for the \(n^{\text{th}}\) term of an AP is:

\(a_n = a + (n-1)\,d\)

Step 3: We are asked: which term is \(210\)?

This means we set \(a_n = 210\).

So, \(210 = 21 + (n-1)\times 21\).

Step 4: Simplify the equation:

\(210 = 21 + 21(n-1)\)

\(210 = 21 + 21n - 21\)

\(210 = 21n\)

Step 5: Divide both sides by 21:

\(n = \dfrac{210}{21} = 10\).

Final Answer: The \(210\) is the 10th term of the AP.

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 5: Arithematic Progressions – Exercise 5.1 | Detailed Answers