NCERT Solutions
Class 10 - Mathematics - Chapter 8: INTRODUCTION TO TRIGONOMETRYExercise 8.2
Class 10 - Mathematics - Chapter 8: INTRODUCTION TO TRIGONOMETRY
Question. 1
Evaluate the following:
- \(\sin 60^\circ \cos 30^\circ + \sin 30^\circ \cos 60^\circ\)
- \(2 \tan^2 45^\circ + \cos^2 30^\circ - \sin^2 60^\circ\)
- \(\dfrac{\cos 45^\circ}{\sec 30^\circ + \text{cosec } 30^\circ}\)
- \(\dfrac{\sin 30^\circ + \tan 45^\circ - \text{cosec } 60^\circ}{\sec 30^\circ + \cos 60^\circ + \cot 45^\circ}\)
- \(\dfrac{5 \cos^2 60^\circ + 4 \sec^2 30^\circ - \tan^2 45^\circ}{\sin^2 30^\circ + \cos^2 30^\circ}\)
Answer:
(i) \(1\)
(ii) \(2\)
(iii) \(\dfrac{3\sqrt{2} - \sqrt{6}}{8}\)
(iv) \(\dfrac{43 - 24\sqrt{3}}{11}\)
(v) \(\dfrac{67}{12}\)
Question. 2
Choose the correct option and justify your choice:
- \(\dfrac{2 \tan 30^\circ}{1 + \tan^2 30^\circ} =\)
(A) \(\sin 60^\circ\) (B) \(\cos 60^\circ\) (C) \(\tan 60^\circ\) (D) \(\sin 30^\circ\) - \(\dfrac{1 - \tan^2 45^\circ}{1 + \tan^2 45^\circ} =\)
(A) \(\tan 90^\circ\) (B) 1 (C) \(\sin 45^\circ\) (D) 0 - \(\sin 2A = 2 \sin A\) is true when \(A =\)
(A) \(0^\circ\) (B) \(30^\circ\) (C) \(45^\circ\) (D) \(60^\circ\) - \(\dfrac{2 \tan 30^\circ}{1 - \tan^2 30^\circ} =\)
(A) \(\cos 60^\circ\) (B) \(\sin 60^\circ\) (C) \(\tan 60^\circ\) (D) \(\sin 30^\circ\)
Answer:
(i) A
(ii) D
(iii) A
(iv) C
Question. 3
If \(\tan (A + B) = \sqrt{3}\) and \(\tan (A - B) = \dfrac{1}{\sqrt{3}}\); \(0^\circ < A + B \leq 90^\circ\), \(A > B\), find \(A\) and \(B\).
Answer:
\(\angle A = 45^\circ,\ \angle B = 15^\circ\)
Question. 4
State whether the following are true or false. Justify your answer.
- \(\sin (A + B) = \sin A + \sin B\).
- The value of \(\sin \theta\) increases as \(\theta\) increases.
- The value of \(\cos \theta\) increases as \(\theta\) increases.
- \(\sin \theta = \cos \theta\) for all values of \(\theta\).
- \(\cot A\) is not defined for \(A = 0^\circ\).
Answer:
(i) False
(ii) True
(iii) False
(iv) False
(v) True