Perpendicular Bisector Theorem of a Chord

Learn the perpendicular bisector property of a chord and how the radius from the centre bisects the chord at 90 degrees.

1. Understanding the Perpendicular Bisector Theorem

The Perpendicular Bisector Theorem states that:

The perpendicular drawn from the centre of a circle to a chord bisects the chord.

This means if you draw a right angle from the centre to a chord, it cuts the chord into two equal parts.

2. Statement of the Theorem

If a radius (or a line from the centre) is perpendicular to a chord at point \(M\), then:

AM = MB

Where \(A\) and \(B\) are endpoints of the chord \(AB\).

3. Why the Theorem is True

When the centre \(O\) is joined to the endpoints of the chord \(A\) and \(B\), two triangles are formed:

  • \(\triangle OAM\)
  • \(\triangle OBM\)

Since:

  • \(OA = OB = r\) (radii)
  • \(OM = OM\) (common side)
  • \(\angle OMA = \angle OMB = 90^\circ\)

The two triangles are congruent, giving:

AM = MB

4. Converse of the Theorem

The converse is also true:

If a line from the centre of the circle bisects a chord, then it is perpendicular to that chord.

So, the direction of the line doesn't matter—bisecting implies perpendicularity.

5. Application in Geometry

This theorem is used to locate the centre of a circle through chords, solve problems involving chord lengths, and prove equalities in diagrams.

5.1. Finding the Centre Using Chords

If two perpendicular bisectors of two different chords are drawn, their intersection gives the centre of the circle.

5.2. Example

In a circle, a chord \(AB\) is \(10\text{ cm}\). If a line from the centre is perpendicular to the chord, then it divides the chord into:

AM = MB = 5\text{ cm}

6. Real-Life Connections

This principle appears in practical situations such as:

  • Designing wheels and gears
  • Locating the centre of circular plates or disks
  • Ensuring symmetry in circular art and patterns