An archery target has three regions formed by three concentric circles whose diameters are in the ratio \(1:2:3\). Find the ratio of the areas of the three regions.

\(1 : 3 : 5\)
Step 1: The diameters are in the ratio \(1:2:3\).
That means the radii are also in the ratio \(1:2:3\), because radius = diameter ÷ 2.
Step 2: The area of a circle depends on the square of its radius:
\( A = \pi r^2 \)
Step 3: Since the radii are in ratio \(1:2:3\), the areas of the full circles will be in the ratio:
\(1^2 : 2^2 : 3^2 = 1 : 4 : 9\).
Step 4: Now find the areas of each region (ring):
Step 5: So the ratio of the areas of the three regions is:
\(1 : 3 : 5\).
Final Answer: \(\boxed{1 : 3 : 5}\)