When a die is thrown, the probability of getting an odd number less than 3 is
\(\dfrac{1}{6}\)
\(\dfrac{1}{3}\)
\(\dfrac{1}{2}\)
0
Step 1: A die has 6 faces. The possible outcomes are: 1, 2, 3, 4, 5, 6.
Step 2: We want an odd number that is also less than 3.
Odd numbers on a die are: 1, 3, 5.
Among these, the numbers less than 3 are only: 1.
Step 3: So, the favorable outcome is only {1}. That means total favorable outcomes = 1.
Step 4: Total possible outcomes when throwing a die = 6.
Step 5: Probability = (Number of favorable outcomes) ÷ (Total outcomes).
= \(\dfrac{1}{6}\).
Final Answer: Option (A).