One ticket is drawn at random from a bag of tickets numbered 1 to 40. The probability that the selected ticket is a multiple of 5 is
\(\dfrac{1}{5}\)
\(\dfrac{3}{5}\)
\(\dfrac{4}{5}\)
\(\dfrac{1}{3}\)
Step 1: Total number of tickets
The tickets are numbered from 1 to 40. So, the total number of possible outcomes = 40.
Step 2: Favourable outcomes
We need tickets that are multiples of 5. Let’s list them:
5, 10, 15, 20, 25, 30, 35, 40
So, there are 8 favourable tickets.
Step 3: Formula for probability
Probability = \(\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}\)
Step 4: Substitute the values
\( P = \dfrac{8}{40} \)
Step 5: Simplify the fraction
\( \dfrac{8}{40} = \dfrac{1}{5} \)
Final Answer: Option (A) \(\dfrac{1}{5}\)