NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 13: Statistics and Probability - Exercise 13.1
Question 7

Question. 7

Consider the distribution:

Class	0–5	6–11	12–17	18–23	24–29
Frequency	13	10	15	8	11

The upper limit of the median class is

(A)

(B)

17.5

(C)

(D)

18.5

Step 1: First, add up all the frequencies to get the total number of observations (N).

\(N = 13 + 10 + 15 + 8 + 11 = 57\)

Step 2: Find \(N/2\).

\(N/2 = 57/2 = 28.5\)

Step 3: Make the cumulative frequencies (keep adding one by one).

For 0–5: \(13\)
For 6–11: \(13 + 10 = 23\)
For 12–17: \(23 + 15 = 38\)
For 18–23: \(38 + 8 = 46\)
For 24–29: \(46 + 11 = 57\)

Step 4: Now check where \(28.5\) lies in the cumulative frequencies.

It is greater than 23 but less than or equal to 38. So, the median class is 12–17.

Step 5: The upper limit of this class (12–17) is 17.

Final Answer: The upper limit of the median class is 17. So, option (A) is correct.