A bag contains slips numbered from 1 to 100. If Fatima chooses a slip at random from the bag, it will either be an odd number or an even number. Since this situation has only two possible outcomes, so, the probability of each is \(\dfrac{1}{2}\). Justify.
Step 1: Total slips in the bag = 100 (from 1 to 100).
Step 2: We need to see how many slips are odd and how many are even.
Step 3: Probability formula (in SI):
\( P(E) = \dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \)
Step 4: Probability of getting an odd slip = \(\dfrac{50}{100} = \dfrac{1}{2}\).
Step 5: Probability of getting an even slip = \(\dfrac{50}{100} = \dfrac{1}{2}\).
Final Step: Since both probabilities are equal and each is \(\dfrac{1}{2}\), the statement is justified.