A coin is tossed two times. Probability of getting at most one head?
\(\dfrac{3}{4}\)
Step 1: Write all possible outcomes.
When a coin is tossed 2 times, the possible outcomes are:
So, the total number of outcomes = 4.
Step 2: Understand the condition "at most one head".
"At most one head" means we can have 0 heads or 1 head. It cannot be more than 1.
Step 3: Find the favourable outcomes.
So favourable outcomes = TT, HT, TH (total 3 outcomes).
Step 4: Apply probability formula.
\( P(E) = \dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \)
\( P(E) = \dfrac{3}{4} \)
Final Answer: \(\dfrac{3}{4}\)