A bag has 10 red, 5 blue, 7 green balls. Probability that a ball drawn is (i) red (ii) green (iii) not blue?
(i) \(\dfrac{5}{11}\), (ii) \(\dfrac{7}{22}\), (iii) \(\dfrac{17}{22}\)
Step 1: Write the total number of balls in the bag.
Total = Red + Blue + Green = 10 + 5 + 7 = 22 balls.
Step 2: Recall the formula for probability:
\( P(E) = \dfrac{\text{Number of favourable outcomes}}{\text{Total outcomes}} \)
(i) Probability of red ball:
Number of red balls = 10
Total balls = 22
So, \( P(\text{red}) = \dfrac{10}{22} = \dfrac{5}{11} \)
(ii) Probability of green ball:
Number of green balls = 7
Total balls = 22
So, \( P(\text{green}) = \dfrac{7}{22} \)
(iii) Probability of not blue ball:
Not blue means: total balls – blue balls = 22 – 5 = 17
So, \( P(\text{not blue}) = \dfrac{17}{22} \)
Final Answer:
(i) \(\dfrac{5}{11}\), (ii) \(\dfrac{7}{22}\), (iii) \(\dfrac{17}{22}\)