A letter of the English alphabet is chosen at random. Probability it is a consonant?
\(\dfrac{21}{26}\)
Step 1: Total letters in the English alphabet = 26.
Step 2: The alphabet is divided into vowels and consonants.
Vowels: A, E, I, O, U → 5 vowels.
Step 3: The remaining letters are consonants.
So, number of consonants = 26 − 5 = 21.
Step 4: Probability formula:
\[ P(E) = \dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} \]
Step 5: Here, favourable outcomes = choosing a consonant = 21.
Total outcomes = all letters = 26.
Step 6: Substitute values:
\[ P(\text{consonant}) = \dfrac{21}{26} \]
Final Answer: \(\dfrac{21}{26}\).