NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 13: Statistics and Probability - Exercise 13.3
Question 35

Question. 35

Box A: 25 slips (19 marked Re 1, 6 marked Rs 5). Box B: 50 slips (45 marked Re 1, 5 marked Rs 13). Slips are mixed and one slip is drawn. Probability it is marked other than Re 1?

Answer:

\(\dfrac{11}{75}\)

Detailed Answer with Explanation:

Step 1: First, find the total number of slips in each box.

  • Box A has 25 slips.
  • Box B has 50 slips.

Total slips = 25 + 50 = 75.

Step 2: Now find how many slips are marked other than Re 1 in each box.

  • In Box A: Out of 25 slips, 19 are Re 1. The remaining 6 are marked Rs 5. These 6 are other than Re 1.
  • In Box B: Out of 50 slips, 45 are Re 1. The remaining 5 are marked Rs 13. These 5 are other than Re 1.

Step 3: Add them together.

Number of slips other than Re 1 = 6 (from Box A) + 5 (from Box B) = 11.

Step 4: Probability formula is:

\( P(E) = \dfrac{\text{Favourable outcomes}}{\text{Total outcomes}} \)

Step 5: Put the values in the formula.

\( P(\text{slip not Re 1}) = \dfrac{11}{75} \)

Final Answer: The probability that the slip is marked other than Re 1 is \(\dfrac{11}{75}\).

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