NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 13: Statistics and Probability - Exercise 13.3

Question 39

Step 1: Understand the die.

The die has 6 faces: 0, 1, 1, 1, 6, 6. That means: one face shows 0, three faces show 1, and two faces show 6.

Step 2: Totals when two dice are thrown.

We add the numbers on both dice to get the total.

• 0 + 0 = 0
• 0 + 1 = 1
• 1 + 1 = 2
• 0 + 6 = 6
• 1 + 6 = 7
• 6 + 6 = 12

So, the different totals possible are: 0, 1, 2, 6, 7, 12. That makes 6 totals.

Step 3: Probability of total = 7.

To get a total of 7, one die must show 1 and the other die must show 6.

• Case A: First die shows 1, second die shows 6.
• Case B: First die shows 6, second die shows 1.

Step 4: Count favourable outcomes.

Probability of 1 on one die = 3/6 (since 3 faces have 1). Probability of 6 on one die = 2/6 (since 2 faces have 6).

For Case A: (3/6) × (2/6) = 6/36

For Case B: (2/6) × (3/6) = 6/36

Total favourable = 6/36 + 6/36 = 12/36.

Step 5: Simplify.

12/36 = 1/3.

Final Answer:

(i) 6 totals possible. (ii) Probability of 7 = 1/3.