NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 5: Arithematic Progressions - Exercise 5.1
Question 1

Question.  1

In an AP, if \(d=-4\), \(n=7\), \(a_n=4\), then \(a\) is

(A)

6

(B)

7

(C)

20

(D)

28

Detailed Answer with Explanation:

We are asked to find the first term \(a\) of the Arithmetic Progression (AP).

Step 1: Recall the formula for the \(n^{th}\) term of an AP:

\(a_n = a + (n - 1) d\)

Step 2: Substitute the given values: \(a_n = 4\), \(n = 7\), \(d = -4\).

So, \(4 = a + (7 - 1)(-4)\).

Step 3: Simplify inside the brackets:

\(7 - 1 = 6\). So,

\(4 = a + (6)(-4)\).

Step 4: Multiply:

\(4 = a - 24\).

Step 5: Add 24 on both sides to find \(a\):

\(a = 4 + 24\).

Step 6: Calculate:

\(a = 28\).

So, the first term \(a\) is 28.

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 5: Arithematic Progressions – Exercise 5.1 | Detailed Answers