NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 5: Arithematic Progressions - Exercise 5.1
Question 2

Question.  2

In an AP, if \(a=3.5\), \(d=0\), \(n=101\), then \(a_n\) will be

(A)

0

(B)

3.5

(C)

103.5

(D)

104.5

Detailed Answer with Explanation:

Step 1: Recall the formula for the n-th term of an arithmetic progression (AP):

\(a_n = a + (n-1) \times d\)

Step 2: Here, \(a = 3.5\), \(d = 0\), and \(n = 101\).

Step 3: Put these values in the formula:

\(a_{101} = 3.5 + (101 - 1) \times 0\)

Step 4: Simplify inside the brackets:

\(a_{101} = 3.5 + 100 \times 0\)

Step 5: Multiply \(100 \times 0 = 0\).

So, \(a_{101} = 3.5 + 0 = 3.5\).

Step 6: This means all terms of the AP are the same (because \(d=0\)), so every term is equal to \(3.5\).

Therefore, the answer is option B (3.5).

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 5: Arithematic Progressions – Exercise 5.1 | Detailed Answers