NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 5: Arithematic Progressions - Exercise 5.1Question 2
Class 10 - Mathematics - CHAPTER 5: Arithematic Progressions - Exercise 5.1
Question. 2
In an AP, if \(a=3.5\), \(d=0\), \(n=101\), then \(a_n\) will be
(A)
0
(B)
3.5
(C)
103.5
(D)
104.5
Detailed Answer with Explanation:
Step 1: Recall the formula for the n-th term of an arithmetic progression (AP):
\(a_n = a + (n-1) \times d\)
Step 2: Here, \(a = 3.5\), \(d = 0\), and \(n = 101\).
Step 3: Put these values in the formula:
\(a_{101} = 3.5 + (101 - 1) \times 0\)
Step 4: Simplify inside the brackets:
\(a_{101} = 3.5 + 100 \times 0\)
Step 5: Multiply \(100 \times 0 = 0\).
So, \(a_{101} = 3.5 + 0 = 3.5\).
Step 6: This means all terms of the AP are the same (because \(d=0\)), so every term is equal to \(3.5\).
Therefore, the answer is option B (3.5).