NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 7: Coordinate Geometry

Exercise 7.2

\(\triangle ABC\) with vertices \(A(-2,0),\ B(2,0),\ C(0,2)\) is similar to \(\triangle DEF\) with vertices \(D(-4,0),\ E(4,0),\ F(0,4)\).

Point \(P(-4,2)\) lies on the line segment joining \(A(-4,6)\) and \(B(-4,-6)\).

The points \((0,5),\ (0,-9),\ (3,6)\) are collinear.

\(P(0,2)\) is the intersection of the y–axis and the perpendicular bisector of the segment joining \(A(-1,1)\) and \(B(3,3)\).

Points \(A(3,1),\ B(12,-2),\ C(0,2)\) cannot be vertices of a triangle.

Points \(A(4,3),\ B(6,4),\ C(5,-6),\ D(-3,5)\) are vertices of a parallelogram.

A circle has centre at the origin and a point \(P(5,0)\) lies on it. The point \(Q(6,8)\) lies outside the circle.

The point \(A(2,7)\) lies on the perpendicular bisector of the segment joining \(P(6,5)\) and \(Q(0,-4)\).

The point \(P(5,-3)\) is one of the two trisection points of the segment joining \(A(7,-2)\) and \(B(1,-5)\).

Points \(A(-6,10),\ B(-4,6),\ C(3,-8)\) are collinear such that \(AB=\dfrac{2}{9}\,AC\).

The point \(P(-2,4)\) lies on a circle of radius 6 and centre \((3,5)\).

The points \(A(-1,-2),\ B(4,3),\ C(2,5),\ D(-3,0)\) in that order form a rectangle.