NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 11: Area Related To Circles - Exercise 11.3
Question 6

Question. 6

Find the area of the flower bed with semicircular ends shown in Fig. 11.6. The overall length is 38 cm and the overall width is 10 cm.

Fig 11.6 (stadium shape 38 by 10)

Answer:

\(280 + 25\pi\;\text{cm}^2\) (≈ 358.50 cm²)

Detailed Answer with Explanation:

Step 1: Identify the shape

The figure looks like a rectangle in the middle with two semicircles (half-circles) attached at the two ends. Together, the two semicircles make one complete circle.

Step 2: Note the given measurements

  • Overall length = 38 cm
  • Overall width (also the diameter of semicircle) = 10 cm

Step 3: Find the radius of the semicircle

Radius = Diameter ÷ 2 = 10 ÷ 2 = 5 cm.

Step 4: Find the length of the rectangular part

The full length = 38 cm. But at both ends we have semicircles of radius 5 cm each, so total semicircle length = 2 × 5 = 10 cm. Rectangular part length = 38 – 10 = 28 cm.

Step 5: Calculate the area of the rectangle

Area = Length × Breadth = 28 × 10 = 280 cm².

Step 6: Calculate the area of the circle formed by the two semicircles

Area of circle = πr² = π × 5² = 25π cm².

Step 7: Add both areas

Total Area = Rectangle area + Circle area = 280 + 25π cm².

Step 8: Approximate value

If we take π ≈ 3.14, 25π ≈ 25 × 3.14 = 78.5. So total area ≈ 280 + 78.5 = 358.5 cm².

Final Answer: 280 + 25π cm² (≈ 358.5 cm²)

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 11: Area Related To Circles – Exercise 11.3 | Detailed Answers