NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 11: Area Related To Circles - Exercise 11.4
Question 18

Question. 18

A circular wheel of area \(1.54\,\text{m}^2\) rolls a distance of \(176\,\text{m}\). Find the number of revolutions made by the wheel.

Answer:

40 revolutions

Detailed Answer with Explanation:

Step 1: Recall the formula for the area of a circle.

The area of a circle is given by \(A = \pi r^2\), where \(r\) is the radius.

Step 2: Substitute the given area.

We are told that the area of the wheel is \(1.54\,\text{m}^2\).

So, \(\pi r^2 = 1.54\).

Step 3: Solve for \(r^2\).

\(r^2 = \dfrac{1.54}{\pi}\).

Taking \(\pi \approx 3.14\):

\(r^2 = \dfrac{1.54}{3.14} \approx 0.49\).

Step 4: Find the radius.

\(r = \sqrt{0.49} = 0.7\,\text{m}\).

Step 5: Find the circumference of the wheel.

The circumference (distance covered in one revolution) is \(C = 2\pi r\).

\(C = 2 \times 3.14 \times 0.7 \approx 4.4\,\text{m}\).

Step 6: Calculate the number of revolutions.

Total distance travelled = \(176\,\text{m}\).

Number of revolutions = \(\dfrac{\text{Total distance}}{\text{Circumference}}\).

\(= \dfrac{176}{4.4} = 40\).

Final Answer: The wheel makes 40 revolutions.

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 11: Area Related To Circles – Exercise 11.4 | Detailed Answers