NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 13: Statistics and Probability - Exercise 13.3
Question 10

Question. 10

10. Cumulative frequency (less-than) of marks of 800 students:

MarksBelow 10Below 20Below 30Below 40Below 50Below 60Below 70Below 80Below 90Below 100
No. of students1050130270440570670740780800

Construct the (ordinary) frequency distribution table.

Answer:

Class0–1010–2020–3030–4040–5050–6060–7070–8080–9090–100
Frequency104080140170130100704020

Detailed Answer with Explanation:

Step 1: Read the given data carefully. The table shows cumulative frequencies (less–than type). For example, “Below 30 = 130” means that 130 students scored less than 30 marks.

Step 2: To convert cumulative frequencies into ordinary frequencies, we need to subtract consecutive values. Why? Because cumulative means “total so far”. Ordinary frequency means “number of students in that specific interval”.

Step 3: Start with the first class (0–10). - Below 10 = 10. - This is the first cumulative value, so frequency for 0–10 = 10.

Step 4: Now calculate the second class (10–20). - Below 20 = 50. - Below 10 = 10. - Frequency for 10–20 = 50 – 10 = 40.

Step 5: For the third class (20–30): - Below 30 = 130. - Below 20 = 50. - Frequency = 130 – 50 = 80.

Step 6: For the fourth class (30–40): - Below 40 = 270. - Below 30 = 130. - Frequency = 270 – 130 = 140.

Step 7: For the fifth class (40–50): - Below 50 = 440. - Below 40 = 270. - Frequency = 440 – 270 = 170.

Step 8: For the sixth class (50–60): - Below 60 = 570. - Below 50 = 440. - Frequency = 570 – 440 = 130.

Step 9: For the seventh class (60–70): - Below 70 = 670. - Below 60 = 570. - Frequency = 670 – 570 = 100.

Step 10: For the eighth class (70–80): - Below 80 = 740. - Below 70 = 670. - Frequency = 740 – 670 = 70.

Step 11: For the ninth class (80–90): - Below 90 = 780. - Below 80 = 740. - Frequency = 780 – 740 = 40.

Step 12: For the tenth class (90–100): - Below 100 = 800. - Below 90 = 780. - Frequency = 800 – 780 = 20.

Step 13: Now write the ordinary frequency distribution table:

Class0–1010–2020–3030–4040–5050–6060–7070–8080–9090–100
Frequency104080140170130100704020

Final Check: Add all frequencies: 10 + 40 + 80 + 140 + 170 + 130 + 100 + 70 + 40 + 20 = 800. This matches the total number of students given. ✔️

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 13: Statistics and Probability – Exercise 13.3 | Detailed Answers