NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 6: Triangles
Exercise 6.3

Proof and application problems on similarity.

Question. 1

In \(\triangle PQR\), suppose \(PR^2 - PQ^2 = QR^2\) and \(M\) lies on \(PR\) with \(QM \perp PR\). Prove that \(QM^2 = PM \cdot MR\).

Answer:

Proved.

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Question. 2

Find the value of \(x\) for which \(DE \parallel AB\) in Fig. 6.8.

Fig. 6.8: Inverted triangle ABC with points D on AC and E on BC. Segments: AD=3x+19, DC=x+3;  BE=3x+4, EC=x.

Answer:

\(x=2\)

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Question. 3

In Fig. 6.9, if \(\angle 1=\angle 2\) and \(\triangle NSQ \cong \triangle MTR\), prove that \(\triangle PTS \sim \triangle PRQ\).

Fig. 6.9: Large triangle PNR with base MQRN, cevians through S and T to Q and R.

Answer:

Proved.

Open

Question. 4

Diagonals of a trapezium \(PQRS\) intersect at \(O\). If \(PQ\parallel RS\) and \(PQ=3\,RS\), find \(\dfrac{\operatorname{ar}(\triangle POQ)}{\operatorname{ar}(\triangle ROS)}\).

Answer:

\(9:1\)

Open

Question. 5

In Fig. 6.10, if \(AB\parallel DC\) and lines \(AC\) and \(PQ\) meet at \(O\), prove that \(OA\cdot CQ = OC\cdot AP\).

Fig. 6.10: Trapezium ABCD with AB ∥ DC, diagonal AC and a line PQ through A and D meeting BC at Q; AC and PQ intersect at O.

Answer:

Proved.

Open

Question. 6

Find the altitude of an equilateral triangle of side 8 cm.

Answer:

\(4\sqrt{3}\,\text{cm}\)

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Question. 7

If \(\triangle ABC \sim \triangle DEF\), with \(AB=4\,\text{cm}\), \(DE=6\,\text{cm}\), \(EF=9\,\text{cm}\) and \(FD=12\,\text{cm}\), find the perimeter of \(\triangle ABC\).

Answer:

18 cm

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Question. 8

In Fig. 6.11, if \(DE\parallel BC\), find \(\operatorname{ar}(ADE):\operatorname{ar}(DECB)\).

Fig. 6.11: Triangle ABC with DE ∥ BC, DE=6 cm, BC=12 cm.

Answer:

\(1:3\)

Open

Question. 9

In trapezium \(ABCD\) with \(AB\parallel DC\), points \(P\) and \(Q\) lie on \(AD\) and \(BC\) respectively, with \(PQ\parallel DC\). If \(PD=18\,\text{cm}\), \(BQ=35\,\text{cm}\) and \(QC=15\,\text{cm}\), find \(AD\).

Answer:

60 cm

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Question. 10

Corresponding sides of two similar triangles are in the ratio \(2:3\). If the area of the smaller is \(48\,\text{cm}^2\), find the area of the larger triangle.

Answer:

108 cm²

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Question. 11

In \(\triangle PQR\), point \(N\) lies on \(PR\) with \(QN\perp PR\). If \(PN\cdot NR = QN^2\), prove that \(\angle PQR = 90^\circ\).

Answer:

Proved.

Open

Question. 12

Areas of two similar triangles are \(36\,\text{cm}^2\) and \(100\,\text{cm}^2\). If a corresponding side of the larger is 20 cm, find the corresponding side of the smaller.

Answer:

12 cm

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Question. 13

In Fig. 6.12, if \(\angle ACB = \angle CDA\), \(AC=8\,\text{cm}\) and \(AD=3\,\text{cm}\), find \(BD\).

Fig. 6.12: Triangle ABC with point D on AB and segment CD drawn.

Answer:

\(\dfrac{55}{3}\,\text{cm}\)

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Question. 14

A 15 m tower casts a 24 m shadow. At the same time a telephone pole casts a 16 m shadow. Find the pole’s height.

Answer:

10 m

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Question. 15

A 10 m ladder leans against a vertical wall with its foot 6 m from the wall. Find the height reached on the wall.

Answer:

8 m

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NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 6: Triangles – Exercise 6.3 | Detailed Answers