NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 7: Coordinate Geometry - Exercise 7.2
Question 8

Question. 8

The point \(A(2,7)\) lies on the perpendicular bisector of the segment joining \(P(6,5)\) and \(Q(0,-4)\).

Answer:

False.

Detailed Answer with Explanation:

To check if a point lies on the perpendicular bisector of a line segment, we must test whether the point is equidistant (same distance) from both end points of the segment.

Step 1: Write the coordinates of all points.

  • \(A(2,7)\)
  • \(P(6,5)\)
  • \(Q(0,-4)\)

Step 2: Use the distance formula:

\( \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \)

Step 3: Calculate distance \(AP\).

\[ AP = \sqrt{(2 - 6)^2 + (7 - 5)^2} = \sqrt{(-4)^2 + (2)^2} = \sqrt{16 + 4} = \sqrt{20} \]

Step 4: Calculate distance \(AQ\).

\[ AQ = \sqrt{(2 - 0)^2 + (7 - (-4))^2} = \sqrt{(2)^2 + (11)^2} = \sqrt{4 + 121} = \sqrt{125} \]

Step 5: Compare the two distances.

We have \(AP = \sqrt{20}\) and \(AQ = \sqrt{125}\).

Conclusion: Since \(AP \neq AQ\), point \(A\) is not equidistant from \(P\) and \(Q\). Therefore, \(A\) does not lie on the perpendicular bisector of the line segment \(PQ\).

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 7: Coordinate Geometry – Exercise 7.2 | Detailed Answers