1. Using Binomial Theorem to Find Specific Coefficients
The binomial theorem makes it easy to find the coefficient of any term in \((a + b)^n\) without expanding the whole expression. Instead of writing all the terms, we directly use the general term formula:
\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]
The coefficient is simply the numerical part of the term.
1.1. Example: Coefficient of \(x^5\) in \((3x - 2)^8\)
We want the term containing \(x^5\).
In the general term:
\[ T_{r+1} = \binom{8}{r} (3x)^{8-r} (-2)^r \]
The power of \(x\) is \(8 - r\). We need:
\(8 - r = 5 \Rightarrow r = 3\)
Now substitute:
\[ T_4 = \binom{8}{3} (3x)^5 (-2)^3 \]
- \(\binom{8}{3} = 56\)
- \((3x)^5 = 243x^5\)
- \((-2)^3 = -8\)
So the term is:
\[56 \cdot 243 \cdot (-8)x^5 = -108864x^5\]
Coefficient = -108864.
2. Approximations Using Binomial Expansion
The binomial theorem helps approximate values of expressions like \((1 + x)^n\) when \(x\) is small. This is useful because multiplying decimals repeatedly can be slow, but the first few terms of the expansion give a close estimate.
The idea is:
\[(1 + x)^n \approx 1 + nx + \dfrac{n(n-1)}{2}x^2 + \cdots \]
For small \(|x|\), higher powers like \(x^3, x^4\) become tiny and can be ignored for quick approximations.
2.1. Example: Approximate \(1.02^5\)
Write 1.02 as \(1 + 0.02\).
Using first three terms:
\[ (1 + 0.02)^5 \approx 1 + 5(0.02) + \dfrac{5 \cdot 4}{2}(0.02)^2 \]
Compute:
- \(5(0.02) = 0.1\)
- \(\dfrac{20}{2}(0.0004) = 10(0.0004) = 0.004\)
So:
\[ 1.02^5 \approx 1 + 0.1 + 0.004 = 1.104 \]
3. Simplifying Algebraic Expressions
Some algebraic expressions are easier to handle after expanding them with the binomial theorem. This method is especially useful when powers are large or when expressions contain combinations of variables.
Expansion helps reveal patterns or allows further simplification.
3.1. Example: Expand and Simplify \((2 + x)^4 - (2 - x)^4\)
Expand each expression using binomial coefficients.
\[(2 + x)^4 = 16 + 32x + 24x^2 + 8x^3 + x^4\]
\[(2 - x)^4 = 16 - 32x + 24x^2 - 8x^3 + x^4\]
Now subtract:
\[(2 + x)^4 - (2 - x)^4 = (16 - 16) + (32x + 32x) + (24x^2 - 24x^2) + (8x^3 + 8x^3) + (x^4 - x^4)\]
Result:
\[64x + 16x^3\]
4. Using Binomial Theorem to Find Terms Near the Beginning or End
Sometimes we need the first few or last few terms of a binomial expansion, especially for approximations or expressions with very high powers.
The binomial theorem helps extract them quickly without expanding the entire series.
4.1. Example: First Three Terms of \((3 - x)^{10}\)
Use the general term formula for \(r = 0, 1, 2\).
Term 1: \(T_1 = \binom{10}{0} 3^{10} (-x)^0 = 59049\)
Term 2: \(T_2 = \binom{10}{1} 3^9 (-x)^1 = -10 \cdot 19683x = -196830x\)
Term 3: \(T_3 = \binom{10}{2} 3^8 (-x)^2 = 45 \cdot 6561x^2 = 295245x^2\)
So, the first three terms are:
\[59049 - 196830x + 295245x^2\]