Fundamental Trigonometric Identities

Learn the three fundamental trigonometric identities connecting sin, cos, tan, sec, cot and cosec with clear explanations and examples.

1. What Are Trigonometric Identities?

A trigonometric identity is an equation involving trigonometric ratios that is true for all valid values of the angle \(\theta\). These identities form the foundation of most trigonometry problems, simplifications and proofs.

The three most important identities come directly from the Pythagorean Theorem.

2. Identity 1: sin²θ + cos²θ = 1

This is the most basic and fundamental identity in trigonometry. It originates from the Pythagorean relation in a right triangle:

\( (\text{Opp})^2 + (\text{Adj})^2 = (\text{Hyp})^2 \)

Dividing all terms by \((\text{Hyp})^2\), we get:

\( \sin^2 \theta + \cos^2 \theta = 1 \)

2.1. Example

If \( \sin \theta = \dfrac{3}{5} \), find \( \cos \theta \).

\( \cos^2 \theta = 1 - \sin^2 \theta = 1 - \dfrac{9}{25} = \dfrac{16}{25} \)

\( \cos \theta = \dfrac{4}{5} \)

3. Identity 2: 1 + tan²θ = sec²θ

This identity is obtained by dividing the main Pythagorean identity by \(\cos^2 \theta\):

\( \dfrac{\sin^2 \theta}{\cos^2 \theta} + 1 = \dfrac{1}{\cos^2 \theta} \)

\( \tan^2 \theta + 1 = \sec^2 \theta \)

3.1. Example

If \( \tan \theta = 2 \), then:

\( \sec^2 \theta = 1 + \tan^2 \theta = 1 + 4 = 5 \)

\( \sec \theta = \sqrt{5} \)

4. Identity 3: 1 + cot²θ = cosec²θ

This identity comes from dividing the fundamental identity by \(\sin^2 \theta\):

\( \dfrac{\cos^2 \theta}{\sin^2 \theta} + 1 = \dfrac{1}{\sin^2 \theta} \)

\( \cot^2 \theta + 1 = \csc^2 \theta \)

4.1. Example

If \( \cot \theta = 3 \), then:

\( \csc^2 \theta = 1 + \cot^2 \theta = 1 + 9 = 10 \)

\( \csc \theta = \sqrt{10} \)

5. Using Identities to Rewrite Ratios

These identities allow us to convert between sin, cos, tan and their reciprocals easily. They are especially useful when simplifying trigonometric expressions or solving equations.

5.1. Example

If \( \sec \theta = 5 \), find \( \tan \theta \).

\( \sec^2 \theta = 25 \)

Using \( \sec^2 \theta = 1 + \tan^2 \theta \):

\( 25 = 1 + \tan^2 \theta \)

\( \tan^2 \theta = 24 \)

\( \tan \theta = \sqrt{24} = 2\sqrt{6} \)