Multiplication Theorem of Probability

Learn the multiplication theorem of probability, including the general rule, the special rule for independent events, and clear examples showing how probabilities of joint events are found.

1. Meaning of the Multiplication Theorem

The multiplication theorem helps find the probability that two events happen together. It is used for situations involving the word “and”.

Examples:

  • Getting a head on a coin and a 4 on a die.
  • Drawing a red card and a king.

It calculates the probability of the intersection of two events.

2. General Multiplication Rule

The general form of the multiplication theorem works for any two events A and B.

\( P(A \cap B) = P(A)P(B|A) \)

This means: the chance of A and B both happening equals the chance of A happening first and then B happening after A.

Similarly,

\( P(A \cap B) = P(B)P(A|B) \)

2.1. Example

Suppose:

  • A: drawing a red card → 26/52
  • B: drawing a king → 4/52

There are 2 red kings.

  • \( P(A \cap B) = 2/52 \)
  • \( P(A) = 26/52 \)
  • \( P(B|A) = 2/26 \)

Using the formula:

\( P(A \cap B) = (26/52)(2/26) = 2/52 \)

3. Multiplication Rule for Independent Events

Two events A and B are independent if the outcome of one does not affect the outcome of the other.

For independent events, the formula becomes simpler:

\( P(A \cap B) = P(A)P(B) \)

This rule is used when the events have no influence on each other.

3.1. Example

Consider:

  • A: getting a head on a coin → 1/2
  • B: getting a 4 on a die → 1/6

The events do not affect each other.

\( P(A \cap B) = (1/2)(1/6) = 1/12 \)

4. Examples of Dependent and Independent Events

The multiplication theorem is useful for understanding whether events influence each other or not.

4.1. Dependent Events Example

Drawing two cards without replacement:

  • A: first card is an ace → 4/52
  • B: second card is an ace (after A happens) → 3/51

\( P(A \cap B) = (4/52)(3/51) \)

4.2. Independent Events Example

Rolling two dice:

  • A: first die shows a 3 → 1/6
  • B: second die shows a 5 → 1/6

\( P(A \cap B) = (1/6)(1/6) = 1/36 \)