NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 6: Triangles - Exercise 6.2Question 2
Class 10 - Mathematics - CHAPTER 6: Triangles - Exercise 6.2
Question. 2
It is given that \(\triangle DEF \sim \triangle RPQ\). Is it true that \(\angle D=\angle R\) and \(\angle F=\angle P\)? Why?
Answer:
No. \(\angle D=\angle R\) is true, but \(\angle F=\angle P\) is false..
Video Explanation:
Detailed Answer with Explanation:
Step 1: The symbol “\(\sim\)” means the two triangles are similar. Similar triangles have their corresponding angles equal and their sides in proportion.
Step 2: When triangles are written in order, the letters tell us which angles match with which.
- In \(\triangle DEF\), the first letter is D.
- In \(\triangle RPQ\), the first letter is R.
- So, \(\angle D \leftrightarrow \angle R\).
Step 3: Next, the second letters correspond:
- In \(\triangle DEF\), the second letter is E.
- In \(\triangle RPQ\), the second letter is P.
- So, \(\angle E \leftrightarrow \angle P\).
Step 4: Finally, the third letters correspond:
- In \(\triangle DEF\), the third letter is F.
- In \(\triangle RPQ\), the third letter is Q.
- So, \(\angle F \leftrightarrow \angle Q\).
Step 5: Therefore:
- \(\angle D = \angle R\) (True)
- \(\angle F = \angle P\) ❌ (False, because F matches with Q, not P)
Final Point: The statement is partly true. Only the first equality is correct.