NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 6: Triangles - Exercise 6.2
Question 11

Question. 11

In Fig. 6.5, if \(\angle D = \angle C\), is it true that \(\triangle ADE \sim \triangle ACB\)? Why?

Answer:

Yes.

Detailed Answer with Explanation:

Step 1: Look at both triangles: \(\triangle ADE\) and \(\triangle ACB\).

Step 2: Notice that \(\angle A\) is present in both triangles. So, they share a common angle.

Step 3: It is given that \(\angle D = \angle C\).

Step 4: Now each triangle has two angles equal:
• In \(\triangle ADE\): angles \(\angle A\) and \(\angle D\).
• In \(\triangle ACB\): angles \(\angle A\) and \(\angle C\).

Step 5: When two angles of one triangle are equal to two angles of another triangle, the two triangles are similar. This rule is called the AA (Angle–Angle) similarity criterion.

Conclusion: Therefore, \(\triangle ADE \sim \triangle ACB\).

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 6: Triangles – Exercise 6.2 | Detailed Answers