NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 7: Coordinate Geometry - Exercise 7.3
Question 1

Question. 1

Name the type of triangle formed by the points \(A(-5,6),\ B(-4,-2),\ C(7,5)\).

Answer:

Scalene.

Detailed Answer with Explanation:

Step 1: Recall the distance formula.

The distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Step 2: Find length of side AB.

Coordinates: \(A(-5, 6), B(-4, -2)\)

\[ AB^2 = (-4 - (-5))^2 + (-2 - 6)^2 \]

\[ AB^2 = (1)^2 + (-8)^2 = 1 + 64 = 65 \]

So, \(AB = \sqrt{65}\).

Step 3: Find length of side BC.

Coordinates: \(B(-4, -2), C(7, 5)\)

\[ BC^2 = (7 - (-4))^2 + (5 - (-2))^2 \]

\[ BC^2 = (11)^2 + (7)^2 = 121 + 49 = 170 \]

So, \(BC = \sqrt{170}\).

Step 4: Find length of side CA.

Coordinates: \(C(7, 5), A(-5, 6)\)

\[ CA^2 = (-5 - 7)^2 + (6 - 5)^2 \]

\[ CA^2 = (-12)^2 + (1)^2 = 144 + 1 = 145 \]

So, \(CA = \sqrt{145}\).

Step 5: Compare the side lengths.

We have:

  • \(AB^2 = 65\)
  • \(BC^2 = 170\)
  • \(CA^2 = 145\)

Since \(65 \neq 170 \neq 145\), all three sides are of different lengths.

Step 6: Check for right triangle.

If it were a right triangle, one side squared would equal the sum of the other two (Pythagoras theorem). But:

  • \(65 + 145 = 210 \neq 170\)
  • \(65 + 170 = 235 \neq 145\)
  • \(145 + 170 = 315 \neq 65\)

So, it is not a right triangle.

Final Conclusion: The triangle has all unequal sides and is not right-angled. Therefore, it is a scalene triangle.

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 7: Coordinate Geometry – Exercise 7.3 | Detailed Answers