NCERT Exemplar Solutions
Class 10 - Mathematics - CHAPTER 7: Coordinate Geometry - Exercise 7.3
Question 7

Question. 7

Find \(m\) if the points \((5,1),\ (-2,-3),\ (8,2m)\) are collinear.

Answer:

\(m=\dfrac{19}{14}\)

Detailed Answer with Explanation:

Step 1: Three points are collinear if the area of the triangle formed by them is 0.

Step 2: Use the area formula for points \((x_1,y_1)\), \((x_2,y_2)\), \((x_3,y_3)\):

\(\text{Area} = \dfrac{1}{2}\left|x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)\right|\).

Step 3: Substitute \((5,1)\), \((-2,-3)\), \((8,2m)\).

  • \(x_1=5,\ y_1=1\)
  • \(x_2=-2,\ y_2=-3\)
  • \(x_3=8,\ y_3=2m\)

Step 4: Compute the expression inside the absolute value:

\(5\big((-3)-2m\big) + (-2)\big(2m-1\big) + 8\big(1-(-3)\big)\)

Simplify term by term:

  • \(5((-3)-2m) = -15 - 10m\)
  • \((-2)(2m-1) = -4m + 2\)
  • \(8(1-(-3)) = 8\times 4 = 32\)

Add them:

\((-15 - 10m) + (-4m + 2) + 32 = 19 - 14m\)

Step 5: For collinearity, area must be zero, so the expression must be zero:

\(|19 - 14m| = 0 \Rightarrow 19 - 14m = 0\)

Step 6: Solve for \(m\).

\(14m = 19\)

\(m = \dfrac{19}{14}\)

Final Answer: \(m = \dfrac{19}{14}\).

NCERT Exemplar Solutions Class 10 – Mathematics – CHAPTER 7: Coordinate Geometry – Exercise 7.3 | Detailed Answers